And on the right-hand side there are only $\text{2}$ moles of $\ce{SO3}$. So ultimately if you consider the reaction to proceed in forward direction 3 moles of gas are converting into 2 moles of gas and hence the volume decreases in forward direction.

Aug 30, 2014 · For the complete molecular orbitals of $\ce{SO3}$ have a look at this question and answer. Apart from this the question is incomplete. In order to determine which orbitals take part in bonding, you have to know the position of the symmetry defining elements. Otherwise the naming of the orbitals is completely interchangeable.

Nov 10, 2014 · C is true because sulfur is solid and SO3 is gas and gases can occupy a large volume when same no. of moles are taken. D is false because if the 2nd and 3rd step have same condition requiring high pressure to force its equilibrium forward …

Mar 8, 2023 · If a benzene ring with an isopropyl group in the first position and bromine in the 3rd position was mixed with SO3 and H2SO4, where would the SO3H attach? Since Br is a deactivating agent that directs ortho/para and isopropyl is a weak activating agent that's also an ortho/para director, would it be in between the two groups in position 2 or in ...

Jul 26, 2015 · Note that $\ce{SO3}$ reacts strongly and rapidly with $\ce{H2O}$ to give $\ce{H2SO4}$. I'd expect this to consume two more equivalents of $\ce{OH-}$ (giving $\ce{SO4^2- + 2H2O)}$, and that those reactions would …

Oct 11, 2016 · The decomposition of $\ce{H2SO4}$ to $\ce{H2O}$ and $\ce{SO3}$ is predominant between $400$ and $700\ \mathrm K$. The formation of a small amount of gaseous sulfuric acid can be observed. Above $673\ \mathrm K$, the equilibrium constant of the reaction R1 becomes higher than 1 and increases rapidly. $$\ce{H2SO4 <=> H2O + SO3}\tag{R1}$$

Sep 7, 2023 · $\ce{SO3}$ reacts with water producing fumes of sulfuric acid. On the contrary it is dissolved into sulfuric acid without fumes, producing oleum. This is why sulfuric acid is used in practice instead of water for absorbing $\ce{SO3}$ produced in the contact process.

Dec 27, 2012 · One atom of oxygen is a fictional species outside of a plasma. Oxygen is naturally diatomic, and the process by which it oxidizes sulfur is radical-based, leading to both oxygen atoms reacting.

Jul 4, 2016 · I guess $\ce{PCl5}$ would wrestle some water from sulfuric acid and drive it to $\ce{SO3}$, or maybe even all the way to $\ce{SO2Cl2}$. $\endgroup$ – Ivan Neretin Commented Jul 4, 2016 at 15:28

Oct 10, 2019 · Back in the day, a competing hypothesis to explain compounds such as $\ce{SO3}$ was proposed: charge separation. In a nutshell, the central sulphur atom does not take part in three double bonds (which would expand the octet) but rather forms two $\ce{\overset{+}{S}-\overset{-}{O}}$ -type single bonds and one regular double bond for a total …