Balance the reaction of Fe + HNO3 = Fe(NO3)3 + NO + H2O using this chemical equation balancer!

Phản ứng Fe + HNO3 loãng (hay sắt tác dụng với HNO3 loãng) sinh ra NO thuộc loại phản ứng oxi hóa - khử thường gặp trong các đề thi. Dưới đây là phản ứng hoá học đã được cân bằng chính xác và chi tiết nhất. Bên cạnh đó là một số bài tập có liên quan về Fe có lời giải, mời các bạn đón đọc. 1. Phương trình hoá học của phản ứng Fe tác dụng với HNO3.

Fe + HNO3 = Fe(NO3)3 + H2 is a Single Displacement (Substitution) reaction where two moles of solid Iron [Fe] and six moles of aqueous Nitric Acid [HNO 3] react to form two moles of aqueous Ferric Nitrate [Fe(NO 3) 3] and three moles of Dihydrogen [H 2] gas

Always use the upper case for the first character in the element name and the lower case for the second character. Examples: Fe, Au, Co, Br, C, O, N, F. Compare: Co - cobalt and CO - carbon monoxide. To enter an ion, specify charge after the compound in curly brackets: {+3} or …

Enter an equation of a chemical reaction and click 'Balance'. The answer will appear below. Always use the upper case for the first character in the element name and the lower case for the second character. Examples: Fe, Au, Co, Br, C, O, N, F. Compare: Co - cobalt and CO - …

In this video we'll balance the equation Fe + HNO3 = Fe (NO3)3 + NO + H2O and provide the correct coefficients for each compound. ...more. To balance Fe + HNO3 = Fe (NO3)3 + NO + H2O...

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Solved and balanced chemical equation Fe + 4 HNO3 → Fe(NO3)3 + NO + 2 H2O with completed products. Application for completing products and balancing equations.

无论是稀还是浓HNO3都具有强氧化性,产物中不可能有H2. 反应方程式如下： Fe+4HNO3(稀）= Fe(NO3)3 + NO(气) + 2H2O. Fe+6HNO3(浓) = FE(NO3)3 + 3NO2(气) + 3H20. 硝酸（nitric acid）分子式为HNO3，是一种有强氧化性、强腐蚀性的无机酸，酸酐为五氧化二氮。硝酸的酸性较硫酸和盐酸小 ...

a Fe + b HNO3 = c N2 + d H2O + f Fe (NO3)3. Create an equation for each element (Fe, H, N, O) where each term represents the number of atoms of the element in each reactant or product. Use substitution, Gaussian elimination, or a calculator to solve for each variable. The resulting matrix can be used to determine the coefficients.