Nov 20, 2014 · The molar volume of a gas at STP is "22.414L/mol". You must convert the given volume of hydrogen gas to liters. Then, using the molar volume, convert the liters to moles. Then convert the moles to mass using the molar mass of hydrogen gas, which is "2.016g/mol" Convert mL "H"_2 to liters. "35.0mL H"_2" x "1 L"/"1000mL" = "0.0350L H"_2 Convert liters "H"_2 to moles. "0.0350L H"_2 x "1 mol H"_2 ...

Jul 8, 2017 · There are 1000 mL (milliliters) in 1 L (liter). So, to convert from mL to L, divide by 1000. I hope this helps a lot! :)

And so when we are quoted a volume of 7.24xx10^2*mL, we make the conversion..... 7.24xx10^2*mL-=7.24xx10^2*cancel(mL)xx10^-3*L*cancel(mL^-1)=0.724*L Such operations are known as "dimensional analysis", and we did a little example in the problem; we wanted an answer with units of concentration and we got one.

Dec 8, 2017 · "H"_ 2"SO"_ (4(aq)) + 2"NaOH"_ ((aq)) -> "Na"_ 2"SO"_ (4(aq)) + 2"H"_ 2"O"_ ((l)) Now, the reaction consumes sulfuric acid and sodium hydroxide in a 1:2 mole ratio, so use the molarities and the volumes of the two solutions to find how many moles of each reactant are present. 60.0 color(red)(cancel(color(black)("mL"))) * ("0.810 moles H"_ 2"SO ...

Apr 19, 2017 · The volume of a gas is equivalent to the number of molecules it contains under equivalent temperature and pressure. And thus we should get 22.4*L HCl(g). We interrogate the reaction: 1/2H_2(g) + 1/2Cl_2(g) rarr HCl(g), equivalently, H_2(g) + Cl_2(g) rarr 2HCl(g), Given the opening statement, i.e. which is due to Avogadro, the volumes are proportional to the number of molecules each gas ...

Jul 19, 2017 · 550 mL 1 L = 1000 mL (0.55 cancel(L))/1 * (1000 mL)/(1 cancel(L)) = 550 mL. If a planet is 13 billion kilometers from the Sun, and the distance of an Astronomical Unit (AU)...

Jan 25, 2017 · To do that, we divide by "NaOH"'s coefficient, and multiply by "H"_2"SO"_4's. n_2 = (8.5xx10^-4 "mol")/2 = 4.25xx10^-4 "mol" There are 4.25xx10^-4 mol of "H"_2"SO"_4. 4: With "H"_2"SO"_4's moles and concentration (given), we can solve for volume. v = n_"2"/c = (4.25xx10^-4 "mol")/("0.110 mol/L") "= 0.003,863,636" L = "3.863,636" mL Significant ...

Apr 19, 2015 · The pressure of Argon under the given conditions is "492 Torr". As you indicated in your question, you will use the ideal gas law to solve this problem. The equation for the ideal gas law is: PV=nRT, where: P is pressure, V is volume, n is moles, R is the gas constant, and T is temperature in Kelvins. The gas constant varies based on the units of your values. I used Wikipedia to find the gas ...

Mar 2, 2018 · I got -2.27 xx 10^(-2) "M/hr". Why is this supposed to be negative? Given the decomposition NH_4NO_2(aq) rarr N_2(g) + 2H_2O(l), if the initial concentration of "NH"_4^(+) was "0.5 M" and it became "0.432 M" after 3 hours, the average rate of decomposition is just asking for: (Delta["NH"_4"NO"_2])/(Deltat) = ? Since we only want the average, we can ignore the fact that the concentration ...

Apr 24, 2016 · "0.0767 mol L"^(-1) The thing to keep in mind when you're dealing with a dilution is that the number of moles of solute must remain constant. That means that the stock solution and the diluted solution will contain the same number of moles of solute. So, your strategy here will be to calculate how many moles of solute, which in your case is …